I have that same book, and I'll admit it, that program gave me quite a headache. It's a little tricky for a beginner programmer. First, you compare the first pair of integers (a and b in the code), and store local min and max somewhere. Do the same thing w
int array [] = {a,b,c,d}; set the max and min value arbitrarily to the first element of the array. int max = array [0]; int min = array [0]; Run the loop to the length of the array and compare each element with the max. If its greater than the max value, update the max value. Likewise compare each element with the min value and if its smaller Largest 10 Digit Number. The largest 10-digit number is 9,999,999,999 because the number that follows it is 10,000,000,000 which is an eleven-digit number. Smallest 10 Digit Number. The smallest 10-digit number is 1,000,000,000 because its preceding number is 999,999,999 which is a nine-digit number. ☛ Related Articles. Numbers Up to 2 DigitsHistory of the world's most popular search engine. Googolplex: A googolplex is 10 raised to the power of a googol. According to the Merriam-Webster online dictionary, it can be expressed as 10The largest four-digit number is 9999. LCM of 2, 3, 5 and 8.= 3 × 5 × 8. ⇒ 120. According to the concept, we know. 120 should divide either 9999 or the four-digit number neat to 9999. When we divide 9999 by 120, we get. Reminder = 39. So, 9999 - 39 = 9960 is divisible by 120. To find the largest 4-digit number that is exactly divisible by 88, we need to divide the largest 4-digit number (9999) by 88 and find the remainder. Step 1: Divide 9999 by 88:9999 ÷ 88 = 113 remainder 55The quotient is 113 and the remainder is 55.Since we are looking for the largest number, we need to subtract the remainder from 9999 to obtain a number that is divisible by 88. . 107 34 261 377 226 57 117 227